(n+2)(n^2-3n+1)=

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Solution for (n+2)(n^2-3n+1)= equation:


Simplifying
(n + 2)(n2 + -3n + 1) = 0

Reorder the terms:
(2 + n)(n2 + -3n + 1) = 0

Reorder the terms:
(2 + n)(1 + -3n + n2) = 0

Multiply (2 + n) * (1 + -3n + n2)
(2(1 + -3n + n2) + n(1 + -3n + n2)) = 0
((1 * 2 + -3n * 2 + n2 * 2) + n(1 + -3n + n2)) = 0
((2 + -6n + 2n2) + n(1 + -3n + n2)) = 0
(2 + -6n + 2n2 + (1 * n + -3n * n + n2 * n)) = 0
(2 + -6n + 2n2 + (1n + -3n2 + n3)) = 0

Reorder the terms:
(2 + -6n + 1n + 2n2 + -3n2 + n3) = 0

Combine like terms: -6n + 1n = -5n
(2 + -5n + 2n2 + -3n2 + n3) = 0

Combine like terms: 2n2 + -3n2 = -1n2
(2 + -5n + -1n2 + n3) = 0

Solving
2 + -5n + -1n2 + n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.

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